Average 49970: 78.76
Avegage 49975: 80.68
ALL Average: 79.67
Median: 79.67
Std Dev: 17.00
Total 100's: 58
\[PV=nRT\]
Boyle's Law: \(P_1V_1 = P_2V_2\) (constant n, T)
Charles' Law: \(\displaystyle{V_1\over T_1} = {V_2\over T_2}\) (constant n, P)
Avogadro's Law: \(\displaystyle{V_1\over n_1} = {V_2\over n_2}\) (constant P, T)
Gay-Lussac's Law: \(\displaystyle{P_1\over T_1} = {P_2\over T_2}\) (constant n, V)
Air Up Your Tires Law: \(\displaystyle{P_1\over n_1} = {P_2\over n_2}\) (constant V, T)
Difficult to Do This Law: \(n_1T_1 = n_2T_2\) (constant P, V)
You will not be tested on the naming of these laws.
and because density (ρ) is m/V and molar mass (M) is m/n, then you also know the molar mass of an ideal gas via:
\[{M={\rho RT\over P}}\]
Dalton's Law of Partial Pressures
\[P_{\rm total}=P_{\rm A} + P_{\rm B} + P_{\rm C} + \cdots\]
mole fraction of gas A: \(x_{\rm A}=P_{\rm A}/P_{\rm total}\)
Van der Waal's Equation of State (Gas Model)
\[\left(P+a{n^2 \over V^2}\right)(V-nb)=nRT\]
Root mean squared velocity of a gas
\[{v_{\rm rms}=\sqrt{3RT \over M}}\]
Comparing rms velocities of two different gases at the same temperature
\[{{v_1\over v_2}=\sqrt{M_2 \over M_1}}\]
The average kinetic energy of an ideal gas
\[E_{\rm k} = U = {3\over 2}RT = {1\over 2}mv^2\]
FYI: There will be no nomenclature (aka naming) on this exam. Nomenclature will be a portion of exam 2.
R = 0.08206 L atm/mol K
R = 62.36 L torr/mol K
R = 0.08314 L bar/mol K
R = 8.314 J/mol K
NA = 6.022 × 1023 mol-1
1 atm = 1.01325 × 105 Pa
1 atm = 760 torr
1 atm = 14.7 psi
1 bar = 105 Pa
1 in = 2.54 cm
1 lb = 453.6 g
1 gal = 3.785 L
\(\rho_{\rm water} = 1.00\) g/mL
\(\rho_{\rm mercury} = 13.6\) g/mL
And now, once again, for your enjoyment...
Students will be able to…..
NEW! 19. Define the compressibility factor (Z) and how its value gives insight into the types of forces in between gas molecules.
You want 'em, you got 'em... The 25 Question Types for Exam 1!